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Expanding Brackets

Expanding Brackets

Expanding Brackets

Expanding brackets is an important step for manipulating expressions, and involves multiplying the terms inside a bracket by those outside of a bracket.

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What does this equal?

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What if we add brackets? What does this equal now?

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So brackets matter for the result!

By the way, notice that when you multiply brackets, you don't need to write the multiplication sign.

3×(4+2)3 \times (4+2) is the same as just 3(4+2)3(4+2)

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Now, you could also work out this problem in a different way

You could also change the expression so that the brackets disappear. That is called expanding the brackets.

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Basically, the 33 wants to be multiplied by both terms inside the brackets. What is 3×43 \times 4?

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And what is 3×23\times2?

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Now, you have 12+612+6

So 12+612+6 is the same as 3(4+2)3(4+2), but you have expanded the brackets - you have made them disappear.

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But why would you want to expand brackets?

It can help you simplify expressions to make them easier to read. This example shows you how.

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To expand the brackets here, you first have to say 2×x2 \times x. What is that?

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Then you say 2×42\times 4. What is that?

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Now the brackets are expanded

Now you can simplify the expression.

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You have 3x3x and another 2x2x. How many xx is that in total?

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So you expanded the brackets to simplify this expression

5x+85x+8 is a lot easier to read than 3x+2(x+4)3x+2(x+4)

Expand 5(3+x)5(3+x)

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Recap! You can expand brackets to simplify expressions

For example, 6x+206x+20 is a lot easier to read than 2x+4(x+5)2x+4(x+5)

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To expand brackets, you need to multiply all the terms inside the brackets by the number outside the brackets

First you say 4×x=4x4 \times x=4x Then you say 4×5=204\times5=20 Then you put the two together 4x+204x+20

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Finally, you can see if you can simplify the whole expression

In this case, you have 2x2x and 4x4x which you can combine to 6x6x

Expand 6(x+2)6(x+2)

Expand (x+6)8(x+6)8

Now, what is 2(x4)2(x-4) when you expand the brackets?

Let's try this one x(3x+6)x(3x+6).

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What happens when the number outside the bracket is also a variable?

We apply the same principle.

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First we multiply x×3xx\times 3x. What does this give us?

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Next we multiply the second term in the bracket. What is x×6x\times 6?

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We have x×3x=3x2x\times 3x=3x^2 and x×6=6xx\times 6=6x.

Putting these together we have 3x2+6x3x^2+6x.

Expand (x2)4x(x-2)4x

Expand and simplify (2+3x)54x(2+3x)5-4x

Expand and simplify x(8+3x)2xx(8+3x)-2x

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Summary! You can expand brackets to simplify expressions

For example, 6x+3x26x+3x^2 is easier to read than x(8+3x)2xx(8+3x)-2x

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So how do you expand brackets?

You multiply both terms inside the bracket by the number outside the bracket.

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The number might follow the brackets rather than stand before them

Don't be confused by that.

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If you multiply a positive and a negative, then remember to keep the minus!

For example, 2×42 \times -4 is 8-8, so this becomes 2x82x-8, not 2x+82x+8

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If you multiply x×xx\times x it becomes x2x^2

So if you multiply x×3xx \times 3x as in this example, it becomes 3x23x^2