If you use a shorter leaver you have to apply more force, which means it will be harder to lift the box.


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The shorter the lever, the harder it is to lift the object.


The shorter the lever, the harder it is to lift the object, so if you only have a short lever, you would have to apply more force than if you had had a longer lever.


Remember $m=F\times d$ where $F$ is the force and $d$ is the distance.


Nope, this is the force required to lift the object. It is not the moment.


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We work it out like this: $m=F\times d=3\times 0.5=1.5\space Newton\space metres$  
  


We work it out like this: $m=F\times d=900\times 1=900\space Newton\space meters$  
  


You will need to get the value and the direction correct.


You have the direction correct, but if we want to balance the see-saw, the magnitude of the force in the clockwise direction has to **equal** the force in the anticlockwise direction.


If the bigger child moves closer to the pivot the moment he applies on his side of the see-saw will be less, so the see-saw will start to balance out even though he is bigger than the other child.


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Oops something went wrong here, the right hand side has a moment of$m=F\times d=1\times 5=5\space Newton\space metres$so in order to balance it out, the left hand side needs to be the same. So you  need to rearrange $m=F\times d$ to make$F$ the subject, so$F=\frac{m}{d}=\frac {5}{0.5}=10\space Newtons$ 
 


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We can use an equation to calculate the moment of a force (size of the rotation).

Calculating the Moment of a Force

Moment of a Force

Gears and Levers

Reducing Unwanted Energy Transfers

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