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Arithmetic Sequences 1

Arithmetic Sequences 1

Arithmetic Sequences 1

Arithmetic sequences are sequences where the difference between terms in the sequence are the same each time. Finding an unknown term in the sequence is called finding the nth term.

1

Is there a pattern in this sequence of numbers? Answer yes or no.

2

How big is the difference between 55 and 88?

3

How big is the difference between 88 and 1111?

4

This is an example of an arithmetic sequence

There is a constant pattern in the sequence of numbers. The difference between each number and the following number is +3+3

1

Is this an arithmetic sequence? Answer yes or no.

2

This is not an example of an arithmetic sequence

The numbers appear more or less random. There is no constant pattern in the sequence.

1

Is this an arithmetic sequence? Answer yes or no.

2

This is an example of an arithmetic sequence

There is a constant pattern. Each number is followed by a number that is +12+12 greater.

What is the next term in this sequence? 4   13   22   31   40   ...4 \space\space\space 13 \space\space\space 22 \space\space\space 31 \space\space\space 40 \space\space\space ...

1

How many terms are listed in this sequence?

2

There are 5 terms in this sequence

You can label them term number 11, 22, 33 , 44 and 55 and call that number label nn

3

What would be the 6th term in this sequence?

4

It's probably not hard to find the 7th, 8th and 9th terms either

But what if you wanted to find the 100th term?!

You can work out a formula that helps you find the value of any nth term in this sequence.

1

To work out this formula, you have to go through a few steps

First you work out how much bigger the value of the term gets every time nn gets 1 bigger.

2

What is the value of the term when n=1n=1 in this sequence?

3

What is the value of the term when n=2n=2?

4

How much bigger does the value of the term get every time nn gets 11 bigger?

5

Every time nn gets one bigger the value of the term gets +3+3 bigger

So the first part of your formula is 3n3n

But 3n3n is not the finished formula! You can call the missing piece of the formula xx

6

Now, what term value should the finished formula give you when n=1n=1?

7

So you can substitute 11 and 77 into the formula like this 3×1+x=73 \times 1 + x = 7. What is xx?

8

So now you have the formula. Try testing it. What do you get if you let n=5n=5?

9

What would be the value of the 50th term in this sequence?

1

What is the difference between the each of the numbers in this sequence?

2

So what do you multiply nn by in the formula for this sequence?

3

Now, let n=1n=1 and work out what the xx in your formula should be.

4

To recap! You found the formula like this

You worked out the difference between each of the numbers in the sequence, which gave you 5n5n

When n=1n=1 the formula should give you 88, so you worked out xx like this 5×1+x=85 \times 1 + x = 8, which means x=3x=3

5

What is the 100th term in this sequence?

What is the 20th term in this sequence? 7   11   15   19...7 \space\space\space 11\space\space\space15\space\space\space19...

1

Summary! This is an arithmetic sequence

There is a constant pattern in the terms in the sequence.

2

Each term can be labelled by a number nn

You use that nn to work out a formula for the sequence, so you can find the value of any nth term in the sequence.

3

To work out the formula, you first find the pattern between the terms

Here they get +3+3 bigger every time nn gets 1 bigger, so the first part of your formula is 3n3n

4

Then you find out what xx is by letting n=1n=1

When n=1n=1, the formula should give 55, so you can work out xx like this 3×1+x=53 \times 1+x=5.

That means that x=2x=2

5

You could now use this formula to work out any nth term

For example, the 10th term in this sequence would be 3×10+2=323 \times 10 +2 = 32